The pressure within a 2.25L balloon is 1.10 ATM if the volume of the balloon increases to 7.05 L what will be the final pressure (in ATM) within the balloon if the temperature does not change?

1 Answer
Junaid Mirza
Feb 18, 2018

#"0.351 atm"#

Explanation:

Boyle’s Law: Pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.

Mathematically,

#P ∝ 1/V#

#P_1V_1 = P_2V_2#

#P_2 = (P_1 V_1)/V_2 = ("1.10 atm" × "2.25 L")/"7.05 L" = "0.351 atm"#

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