The product of #a+3# and #-2a^2+15a+6# is #-2a^3+xa^2+51a+18#. What is the value of #x#?

1 Answer
EZ as pi
Jun 16, 2016

#x = 9#

Explanation:

The method here is to equate the coefficients.
Find the product and then compare the like terms:

#(a+3)(-2a^2 + 15a +6)#

#=-2a^3 +15^2 + 6a - 6a^2+45a +18#

#=-2a^3 +9a^2 + 51a +18 " compare this with"#
#=-2a^3 +xa^2 + 51a +18#

It is clear that#x = 9#

Related questions
Impact of this question
3096 views around the world
You can reuse this answer
Creative Commons License