The reaction between #H_2# and #O_2# produces 13.1 g of water. How many grams of #O_2# reacted? #2H_2(g) + O_2(g) -> 2H_2O(g)#?

1 Answer
Nov 20, 2016

Answer:

Approx. #12*g# of dioxygen gas.

Explanation:

There are #(13.1*g)/(18.01*g*mol^-1)=0.727*mol# of water product.

#H_2(g) + 1/2O_2(g) rarr H_2O(l)#

Given the stoichiometry of the reaction, there were necessarily #0.727*mol# dihydrogen reactant, and #(0.727*mol)/2# dioxygen reactant. I speak of dihydrogen, dioxygen etc. because I wish to avoid the confusion of mistaking atoms for molecules and vice versa.

#"Mass of dioxygen reactant "=(0.727*mol)/2xx32.00*g*mol^-1=??g#