The repeating decimal, #0\bar (.27)#, is converted to the fraction #0.\bar(27) = 3/x#. What is the value of #x# in the fraction?
1 Answer
Oct 21, 2017
Explanation:
The key here is to get rid of the repeating decimal. I do that by multiplying by a term, on both sides, to get one set of repeating decimal isolated. In this case, I'll multiply by 100 to achieve:
And now subtract E1 from E2:
And now I can solve:
Checking: