The repeating decimal, #0\bar (.27)#, is converted to the fraction #0.\bar(27) = 3/x#. What is the value of #x# in the fraction?

1 Answer

#x=11#

Explanation:

#E1: 0.bar(27)=3/x#

The key here is to get rid of the repeating decimal. I do that by multiplying by a term, on both sides, to get one set of repeating decimal isolated. In this case, I'll multiply by 100 to achieve:

#E2: 27.bar(27)=300/x#

And now subtract E1 from E2:

#E2 - E1: 27=300/x-3/x=297/x#

And now I can solve:

#27=297/x#

#x=297/27=11#

Checking:

#3/11=0.bar(27)#