# The solubility of manganese(II) sulphate at 20oC is 62.9g/100g H2O. How many grams of manganous(II)sulphate penta-hydrate crystal must be added to 51L H2O to make a saturated solution?

Oct 25, 2017

Well you gots $51 \cdot L$ water.....and you need approx. $51 \cdot k g$ of the hydrate.....

#### Explanation:

And we got 51*Lxx1000*g*"water"*L^-1xx(62.9*g*"salt")/(100*g*"water")

$= 32079 \cdot g$

And so we need to add a trifle over $32 \cdot k g$ with respect to $M n S {O}_{4} \left(s\right)$.....i.e. $\frac{32.08 \times {10}^{3} \cdot g}{152.0 \cdot g \cdot m o {l}^{-} 1} = 211.05 \cdot m o l$.

And with respect to the pentahydrate, this represents a mass of....

$211.05 \cdot m o l \times 241.05 \cdot g \cdot m o {l}^{-} 1 = 50.9 \cdot k g$....

And by the way what does $\text{saturated solution}$ mean?