# The specific heat of aluminum is 0.214 cal/g°c. What is the energy, in calories, necessary to raise the temperature of a 55.5 g piece of aluminum from 23.0 to 48.6°C?

##### 1 Answer

#### Answer:

#### Explanation:

The **specific heat** of aluminium tells you the amount of energy needed to increase the temperature of

#c_ "Al" = "0.214 cal g"^(-1)""^@"C"^(-1)#

You can thus say that in order to increase the temperature of

Now, you know that your sample has a mass of

#55.5 color(red)(cancel(color(black)("g"))) * "0.214 cal"/(1color(red)(cancel(color(black)("g"))) * 1^@"C") = "11.877 cal"""^@"C"^(-1)#

So, you now know that in order to increase the temperature of

But since you know that the temperature change is equal to

#48.6^@"C" - 23.0^@"C" = 25.6^@"C"#

you can say that you will need

#25.6 color(red)(cancel(color(black)(""^@"C"))) * overbrace("11.877 cal"/(1color(red)(cancel(color(black)(""^@"C")))))^(color(blue)("for 55.5 g of Al")) = color(darkgreen)(ul(color(black)("304 cal")))#

The answer is rounded to three **sig figs**.