Question

The specific heat of water is 4.184 J/g times celsius degree. How much heat is required to raise the temperature of 5.0g of water by 3.0 C degrees?

Answer 1

62.76 Joules

Explanation:

By using the equation:
`Q=mcDeltaT`
`Q` is the energy input in joules.
`m` is the mass in grams/ kg.
`c` is the specific heat capacity, which can be given Joules per kg or Joules per gram per kelvin/Celcius. One must be observant if it is given in joules per kg per kelvin/Celcius, kilojoules per kg per kelvin/Celcius etc. Anyhow, In this case we take it as joule per gram.
`DeltaT` is the temperature change (in Kelvin or Celcius)
Hence:
`Q=mcDeltaT`
`Q=(5 times 4.184 times 3)`
`Q=62.76 J`