The square of the first added to twice the second is 5, what are the two integers?
There are an infinite number of solutions, the simplest and only positive integer solutions being 1 and 2.
If they are supposed to be consecutive integers, then the solution with negatives is the first is
The positive solution is: first is
Assuming that these are supposed to be consecutive integers and the lesser integer is the first, then we can use:
The square of the first is
(Note that this is not a linear equation. It is quadratic.)
If we check the answer, we get
#(-3)^2+ 2(-2) = 9+(-4)=5#
If we check this answer, we get
#(1)^2+2(2) = 1+4 =5#