Question

The standard form of `y = 6(x - 1)^3 ­- 8(x-3)^2`?

Answer 1

`y = 6x^3-26x^2+66x-78`

Explanation:

The easiest way to go about this is by expanding and simplifying.
These are the two expansions you'll need to know to solve this:
Expansion of `(a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3`
Expansion of `(a+b)^2 = a^2 + 2ab + b^2`

Applying these two formulas, we can get the final answer:
`y = 6(x-1)^3 - 8(x-3)^2`
`y = 6(x^3-3x^2+3x-1) - 8(x^2-6x+9)`
`y = 6x^3-18x^2+18x-6 - 8x^2+48x-72`
`y = 6x^3-26x^2+66x-78`