The standard form of #y = (x +1)^3 - (3x-2)^2#?

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Answer 1 · 2018-01-06T06:37:38

Standard form is

#color(green)(y = x^3 - 6x^2 + 15x - 3)#

#y = (x+1)^3 - (3x-2)^2#

Expanding the terms

#y = (x^3 + 1 + 3x(x+1)) - (9x^2 + 4 - 12x)#

Removing the braces,

#y = x^3 + 1 + 3x^2 + 3x - 9x^2 - 4 + 12x##

Rearranging the like terms together and the polynomials in descending order to get the standard form

#y = x^3 + 3x^2 - 9x^2 + 3x + 12x + 1 - 4#

Combining the like terms and simplifying,

#color(green)(y = x^2 - 6x^2 + 15x - 3)#

The standard form of #y = (x +1)^3 ­- (3x-2)^2#?