# The sum of 4 consecutive numbers is 130, how do you find the 4 numbers?

May 2, 2018

Set up an equation where n = the first number and n +1 the second and n+2 the third and n+3 is the fourth.

#### Explanation:

$n + \left(n + 1\right) + \left(n + 2\right) + \left(n + 3\right) = 130$

Combine like terms

$4 n + 6 = 130$ subtract 6 from both sides

$4 n + 6 - 6 = 130 - 6$ which gives

$4 n = 124$ Divide both sides by 4

$4 \frac{n}{4} = \frac{124}{4}$ so

$n = 31$
$n + 1 = 32$
$n + 2 = 33$
$n + 3 = 34$