Question

The sum of 5 consecutive even integers is 160. find the integers. what is the answer to this problem?

pls helpp

Answer 1

The five consecutive numbers are `30`, `31`, `32`, `33`, and `34`.

Explanation:

Let's call the smallest of the five numbers `x`. That means that the following four numbers are `x+1`, `x+2`, `x+3`, and `x+4`.

We know that the sum of these four numbers has to be `160`, so we can set up an equation and solve for `x`:

`(x)+(x+1)+(x+2)+(x+3)+(x+4)=160`

`x+x+1+x+2+x+3+x+4=160`

`5x+1+2+3+4=160`

`5x+10=160`

`5x=150`

`x=30`

Since we set `x` to be the smallest of the five numbers and `x` is `30`, that means that the smallest of the five numbers is `30`. Therefore, the other four numbers are `31`, `32`, `33`, and `34`.

Hope this helped!

Answer 2

30, 31, 32, 33, 34

Explanation:

Let `n` be an integer, for the next integer to be consecutive to it, you add 1 to it correct?
Consecutive integer to n: `n+1`
Consecutive integer to `n+1`= `n+2`
Consecutive integer to `n+2`= `n+3`
Consecutive integer to `n+3`= `n+4`

Alright so:
`n+(n+1)+(n+2)+(n+3)+(n+4)= 160`
`5n+10= 160`
`5n= 150`
`n=30`

So the integers are
`n=30`
`n+1= 30+1= 31`
`n+2= 30+2= 32`
`n+3= 30+3= 33`
`n+4= 30+4= 34`