The sum of three consecutive integers is 123. What would be the three integers?
The 3 integers are 40, 41, and 42.
Let n = the first integer, then n + 1, is second, and n + 2, is the third:
The three integers are
There are two ways to solve this problem.
A] Since we are looking for three consecutive integers that add up to
It follows that the first and third integers will be that integer minus and plus one respectively.
Hence, the three integers are
B] The other way to solve this problem involves very basic algebra (even though this question is in Prealgebra), in which we represent the first integer as
Since we know the sum of these three integers is
Divide each side by
Hence the three consecutive integers are