# The sum of three consecutive integers is 192, what are the integers?

Call your starting integer $n$:
$n + \left(n + 1\right) + \left(n + 2\right) = 192$
$3 n + 3 = 192$
$3 n = 189$
$n = 63$
$63 + 64 + 65 = 192$