# The sum of three consecutive integers is 53 more than the least of the integers, how do you find the integers?

Jun 2, 2015

The integers are: $25 , 26 , 27$

If you assume, that the smallest number is $x$ then the conditions in the task lead to equation:

$x + x + 1 + x + 2 = 53 + x$
$3 x + 3 = 53 + x$
$2 x = 50$
$x = 25$

So you get the numbers: $25 , 26 , 27$