# The sum of two consecutive even integers is 50. What are the numbers?

First even $= 24$
Second even $= 26$

#### Explanation:

let $2 x$ be the first even integer
let $2 x + 2$ be the second even integer

$2 x + \left(2 x + 2\right) = 50$

$4 x = 48$

$x = 12$

First even integer

$2 x = 2 \left(12\right) = 24$

Second even integer

$2 x + 2 = 2 \left(12\right) + 2 = 26$

God bless....I hope the explanation is useful.

Jul 14, 2016

$24 , 26$

#### Explanation:

Note that even integers occur after every odd integer ($\textcolor{b l u e}{6}$, 7, $\textcolor{b l u e}{8}$). Let's write an equation.

One integer can be $n$. The other one must be $n + 2$ since an even integer occurs every two numbers.

$n + \left(n + 2\right) = 50$

This is our equation. We need to solve for $n$.

$2 n + 2 = 50$

$2 n = 48$

$n = 24$

We found that $n$ is $24$. This means that the other even integer, $n + 2$, is $26$. We can go ahead and add these values to see if it equals $50$.

$24 + 26 = 50$

It does equal $50$, so our numbers are correct.