The sum of two consecutive odd integers in 112, what are the integers?

1 Answer
May 31, 2015

55 and 57

Let the first number be n
$n + \left(n + 2\right) = 112$ simplifies to $2 n = 110$ divide by two $n = 55 \mathmr{and} \left(n + 2\right) = 57$