The sun's angular diameter is measured to be 1920". The distance D of the sun from the earth is 1.496×10power11meter. Find the diameter of the sun? {Hint:d=aD}

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Answer 1 · 2018-04-23T07:07:19

# d = 1.496 times 10^{11} cdot 1920/3600 cdot {2 pi}/360 = 1.39254×10^9 # meters

Well now I have to look up what the double quote means. Probably minutes or seconds.

OK, Wikipedia says For example, 40.1875° = 40° 11' 15" .

That's 40 degrees, 11 minutes, 15 seconds, a minute being 1/60th of a degree and a second being 1/60th of a minute. (Thank you Babylonians.)

So we're to understand 1920" as

# 1920/3600 # degrees # = 1920/3600 cdot {2 pi}/360 # radians

So we're looking at a diameter

# d = 1.496 times 10^{11} cdot 1920/3600 cdot {2 pi}/360 # meters

# d = 1.39254×10^9 # meters

Check: Google #quad sqrt#

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