The surface area of a Rubik's cube is 54 sq in. What are the dimensions of each face?

1 Answer
Nov 26, 2015

3 x 3 x 3.

Explanation:

Total Area = (Number of faces) . (Area of one face)
54 = 6 * (Area of one face)
(Area of one face) = 54/6 = 9
(Area of one face) = a^2 =9
a= 3
The cube is 3in X 3in X 3in cube