The temperature of a sample of iron with a mass of 10.0 g changed from 50.4°C to 25.0°C with the release of 114 J of energy. What is the specific heat of iron?

1 Answer
Aug 1, 2016


c = 449 J kg⁻¹ K⁻¹


The equation needed to solve this problem is the specific heat capacity equation: #ΔQ = mc Δ θ#
Where the terms are as follows:
- ΔQ is heat energy transferred (in J)
- m is the mass (in kg)
- c is the specific heat capacity (in J kg⁻¹ K⁻¹)
- Δθ is the temperature chance (in K or ºC)

The only unit conversion necessary is for the mass: #10.0 g = 0.010 kg#

To solve for the specific heat rearrange the equation and substitute the values in.
#c = (ΔQ) / (m Δθ) = 114 / (0.010 × (50.4 - 25.0)) = 448.81…#

To 3 sig. figs c = 449 J kg⁻¹ K⁻¹