Question

The temperature of a sample of water changes from 10°C to 20°C when the water absorbs 420 joules of heat. What is the mass of the sample?

Answer 1

`10.03` grams

Explanation:

The problem can be solved using the formula:

`Q=mCpDeltaT`

where:

`Q=heat`
`m=mass`
`Cp=sp. heat`
`DeltaT=temperature` change `(T_2-T_1)`

Some data are provided in the problem like
`Q=420` Joules
`T_2=20^oC`
`T_1=10^oC`
and the #`[specific heat](http://socratic.org/chemistry/thermochemistry/specific-heat) of water is known to be`4.186 (J)/(g.^oC)#. (http://www.calculator.org/property.aspx?name=specific%20heat%20capacity)

All you have to do is to rearrange the original formula to isolate `m` and to derive the new formula which is;

`m=(Q)/(CpDeltaT)`, plug in values and make sure to cancel out units.
until you have the desired unit.