The temperature of a sample of water increases from 20.0 to 46.6 degrees C as it absorbs 5650J of thermal energy. What is the mass of the sample?

1 Answer
Junaid Mirza
Apr 10, 2018

#"50.7 g"#

Explanation:

Use this equation

#"Q = mC"Δ"T"#

Where

  • #"Q ="# Energy absorbed/released
  • #"m ="# Mass of sample
  • #"C ="# Specific heat of sample (#"4.186 J/g°C"# for water)
  • #Δ"T ="# Temperature change

#"m" = "Q"/("C"Δ"T") = "5650 J"/"4.186 J/(g°C) × (46.6°C - 20°C)" = "50.7 g"#

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