Question

The time period of S.H.M of a particle is 12 seconds. What is the phase difference between the position at t=3 s and t=4 s?please give a detailed explanation.

Answer 1

We can write the equation of S.H.M for this particle as,

`y = a sin omegat` (where, `a` is the amplitude)

So,phase at `t=3s` is `omega*3 = (2pi)/T *3 = (6pi)/12=pi/2`

And,phase at `t=4s` is, `(8pi)/12 = (2pi)/3`

So,phase difference between the two position is `(2pi)/3 - pi/2 =pi/6`