The time t required to drive a certain distance varies inversely with the speed r. If it takes 2 hours to drive the distance at 45 miles per hour, how long will it take to drive the same distance at 30 miles per hour?

1 Answer
Nov 12, 2017

3 hours

Solution given in detail so you can see where everything comes from.

Explanation:

Given

The count of time is #t#
The count of speed is #r#

Let the constant of variation be #d#

Stated that #t# varies inversely with #r color(white)("d") ->color(white)("d") t=d/r#

Multiply both sides by #color(red)(r)#

#color(green)(t color(red)(xxr)color(white)("d")=color(white)("d")d/rcolor(red)(xxr))#

#color(green)(tcolor(red)(r)=d xx color(red)(r)/r)#

But #r/r# is the same as 1

#tr=d xx 1#

#tr=d# turning this round the other way

#d=tr#

but the answer to #tr# ( time x speed ) is the same as distance
So #d# must be the distance.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Part 1 - Determine the distance traveled - initial condition")#

We are given that the initial time #t# is 2 yours
We are given that the initial speed #r# is 45 miles for each hour.

So the initial distance driven #d# is such that: #d=2 xx 45 = 90#

How do we handle the units of measurement. They behave the same way as do the numbers.

So we have:

#color(green)(d" miles"=color(red)(2cancel("hours")) xx color(purple)(45(" miles")/cancel("hours")) = 90" miles ")......Equation(1)#
Notice that the unit for hours cancels out leaving just miles

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Part 2 - Determine the new time for an increase in speed - new condition")#
Instead of writing miles use the letter #m#
Instead of writing hours use the letter #h#

So #Equation(1)# becomes:

#color(green)(dm=color(red)(2cancel(h)) xx color(purple)(45(m)/cancel(h)) = 90m)" "......Equation(1_a)#

In the new condition we do not know time so write #th#
The new speed is 30 miles per hour so write #30 m/h#
The distance traveled is the same so write #90m#

#color(green)(dm=color(red)(tcancel(h)) xx color(purple)(30(m)/cancel(h)) = 90m)" "......Equation(1_b)#

#txx30=90#

Multiply each side by #1/30#

#txx30/30=90/30#

#txx1=3#

#t=3#

But #t# is measured in hours so #t=3# hours