The top floor of the building is a rectangle whose perimeter is 320 feet. The width is 30 feet less than the length. What is the width of the rectangle?

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The top floor of the building is a rectangle whose perimeter is 320 feet. The width is 30 feet less than the length. What is the width of the rectangle?

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Answer 1 · 2018-05-14T11:04:28

Width, $w$ $w$ = $65$ $65$ feet

Explanation:

Perimeter of a rectangle is $2 l + 2 w$ $2l+2w$ or $2 (l + w)$ $2(l+w)$ , where $l$ $l$ is the length and $w$ $w$ is the width.

So now, Perimeter is 320 feet.
Length, $l$ $l$ = $l$ $l$
Width, $w$ $w$ = $l - 30$ $l-30$

So now the equation becomes:

$320 = 2 (l + (l - 30))$ $320 = 2(l + (l-30))$
$320 = 2 (2 l - 30)$ $320 = 2(2l-30)$
$320 = 4 l - 60$ $320 = 4l-60$
$320 + 60 = 4 l$ $320+60=4l$
$380 = 4 l$ $380=4l$

$\frac{380}{4} = l$ $380/4=l$

$95 = l$ $95=l$

So we get Lent, $l$ $l$ = 95 $f e e t, and W i d t h,$ $feet, and Width,$ w $=$ $=$ $95 - 30 = 65$ $95-30=65$
feet

So Width, $w$ $w$ = $65$ $65$ feet

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The top floor of the building is a rectangle whose perimeter is 320 feet. The width is 30 feet less than the length. What is the width of the rectangle?

1 Answer

Explanation:

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