The top floor of the building is a rectangle whose perimeter is 320 feet. The width is 30 feet less than the length. What is the width of the rectangle?

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Answer 1 · 2018-05-14T11:04:28

Width,#w# = #65# feet

Perimeter of a rectangle is #2l+2w# or #2(l+w)#, where #l# is the length and #w# is the width.

So now, Perimeter is 320 feet.
Length, #l# = #l#
Width, #w# = #l-30#

So now the equation becomes:

#320 = 2(l + (l-30))#
#320 = 2(2l-30)#
#320 = 4l-60#
#320+60=4l#
#380=4l#

#380/4=l#

#95=l#

So we get Lent, #l# = 95# feet, and Width, #w# = ##95-30=65#
feet

So Width,#w# = #65# feet