# The value of 3 times the square root of 8 is between which two consecutive integers?

$8 < 3 \sqrt{8} < 9$
You have ${\left(3 \sqrt{8}\right)}^{2} = 72$ and
${8}^{2} < 72 < {9}^{2}$ so
$8 < 3 \sqrt{8} < 9$