The vector sum of the forces of 10N and 6N can be?
1 Answer
May 14, 2018
Explanation:
-
In this formula, R is the size of the total vector,
#F_1 " and " F_2 # are the magnitudes of the summed vectors, and theta is the angle between the two vectors. -
# theta" " # angle can take values from 0 to 180. -
if
#theta" "=0 " "cos (theta)=1# -
#R=sqrt(10^2+6^2+2*10*6)=sqrt(100+36+120)=sqrt(256)=16N# -
if
#theta" "=180 " "cos (theta)=-1# -
#R=sqrt(10^2+6^2-2*10*6)=sqrt(100+36-120)=sqrt(16)=4N# -
the magnitudes of the vector sum can take values from 4 N to 16 N.
-
#4<=R<=16#