The vector sum of the forces of 10N and 6N can be?
1 Answer
May 14, 2018
Explanation:
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In this formula, R is the size of the total vector,
F_1 " and " F_2 are the magnitudes of the summed vectors, and theta is the angle between the two vectors. -
theta" " angle can take values from 0 to 180. -
if
theta" "=0 " "cos (theta)=1 -
R=sqrt(10^2+6^2+2*10*6)=sqrt(100+36+120)=sqrt(256)=16N -
if
theta" "=180 " "cos (theta)=-1 -
R=sqrt(10^2+6^2-2*10*6)=sqrt(100+36-120)=sqrt(16)=4N -
the magnitudes of the vector sum can take values from 4 N to 16 N.
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4<=R<=16