Question

The volume of a balloon is 6.52 L at 32.5 ºC and 762 mm Hg pressure. What volume in mL will the balloon have at standard temperature and pressure (STP)?  

The volume of a balloon is 6.52 L at 32.5 ºC and 762 mm Hg pressure. What volume in mL will the balloon have at standard temperature and pressure (STP)?

Answer 1

STP = `0^oC` `(273^oK)` and 1 atm (760mmHg)
`V_2 = 5840 mL`

Explanation:

The change is calculated from the ideal gas laws:

`((PV)/T)_1 = ((PV)/T)_2`

`((762 xx 6.52)/305.5) = ((760 xx V)/273)`

`V_2 = ((762 xx 6.52)/305.5)/(760/273)`

`V_2 = 16.26/2.78 = 5.84L`

`5.84L xx 1000(mL)/L = 5840 mL`