The width of the ohioa community pool is 20 feet.the length is twice as its widh.what is the perimeter of the pool?

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Answer 1 · 2018-06-23T22:58:55

See a solution process below:

We are told in the problem the width of the pool, or #w#, is: #20" ft"#

We are also told length of the pool, or #l# is twice the width.

Therefore the length of the pool is: #l = 2 xx w = 2 xx 20" ft" = 40" ft"#

The formula for the perimeter of a rectangle is:

#P = 2(l + w)#

Substituting and solving for #P# gives:

#P = 2(40" ft" + 20" ft")#

#P = 2 xx 60" ft"#

#P = 120" ft"#

The perimeter of the pool is #color(red)(120" ft")#