The zeros in: $(x^{3}) + (2 x^{2}) - 5 x - 6 = 0$ $(x^3)+(2x^2)-5x-6=0$ ?

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Answer 1 · 2018-03-20T19:48:50

$x = - 3$ $x=-3$
$x = - 1$ $x=-1$
$x = 2$ $x=2$

[0] $x³+2x²-5x-6$
[1] $(x+1)(x²+x-6)$
[2] $(x+1)(x-2)(x+3)$
So zeros are only when one of the three terms is equal to zero.

The zeros in: (x^3)+(2x^2)-5x-6=0(x3)+(2x2)−5x−6=0(x^3)+(2x^2)-5x-6=0 ?