There are 10 persons named (A,B,.......J).we have the capacity to accommodate only 5. In how many ways can we arrange them in a line if A is must and G and H must not be included in the team of 5?

1 Answer

#=^7C_3\times5!#

Explanation:

Since, G & H are not to be selected & A is must out of 10 persons then

hence the number of way of selecting #4# persons out of 7 persons
#=^7C_4#

Then A+4 other persons are arranged in a line in following number of ways

#=5!#

hence, total number of ways of selecting & arranging 5 persons in a line

#=^7C_4\times 5!#

#=^7C_3\times5!#