Question

This question is using the concept Law of multiple proportions, how cn I use that law to solve this problem?

Answer 1

Option 2 has the correct ratio for Compound 2.

Explanation:

The Law of Multiple Proportions states that when two elements A and B combine to form two or more compounds, the masses of B that combine with a given mass of A are in the ratios of small whole numbers.

Compound 1

In Compound 1, the mass ratio of A:B is `46.7: 53.3`.

If we divide both sides of the ratio by 46.7, it becomes `1:1.14`.

In other words, 1 g A combines with 1.14 g B.

Law of Multiple Proportions

Now, let's do the same calculation for each of the options given for Compound 2.

`ulbb("Option"color(white)(m)"Ratio"color(white)(mm)"Normalized")`
`color(white)(mm)1color(white)(mm)23.4:76.6color(white)(mmm)1:3.27`
`color(white)(mm)2color(white)(mm)30.4:69.6 color(white)(mmm)color(red)(1:2.28)`
`color(white)(mm)3color(white)(mm)73.3:76.7color(white)(mmm)1:0.38`

In Compound 1, 1 g A reacts with 1.14 g B
In Compound 2, 1 g A reacts with 2.28 g B

The ratio of the masses of B in the two compounds is

`1.14:2.28 = 1:2`

Option 2 has the correct ratio for Compound 2.