Question

Three concurrent forces of same magnitude are in equilibrium. What is the angle between the forces? Also name the triangle formed by the forces as sides??

Answer 1

See the image,it depicts the triangle,it is an equilateral triangle,and angle between two forces is `180-60=120` degrees

So,resultant of any two vectors have equal magnitude and directed along the opposite direction of the 3rd.

Let, resultant of the two forces excepting the base of the trinagle is `sqrt(F^2 +F^2 + 2F F cos 120)=F`

Which is directed just opposite to the vector represented by the base of the triangle,so angle between them is `180`

So,their resultant is `sqrt(F^2 +F^2 + 2F F cos 180)=0`