# Three consecutive even integers have a sum of 48. What are the integers?

Oct 20, 2016

The three consecutive even numbers are $14 , 16 , \mathmr{and} 18$

#### Explanation:

Let color(red)(n_ be the smallest even integer.
Therefore the other two consecutive even integers will be: $\textcolor{b l u e}{n + 2}$ and $\textcolor{g r e e n}{n + 4}$

We are told
$\textcolor{w h i t e}{\text{XXX}} \textcolor{red}{n} + \textcolor{b l u e}{n + 2} + \textcolor{g r e e n}{n + 4} = 48$

$\rightarrow 3 n + 6 = 48$

$\rightarrow 3 n = 42$

$\rightarrow n = 14$