Three of the letters of SPINS are randomly selected to form a word. How many different words are possible? These words do not have to be real words, for example, spn is one of the words.

1 Answer

33 "words"

Explanation:

This is a permutation problem where we care about the order of the letters. The general formula is:

#P_(n,k)=(n!)/((n-k)!); n="population", k="picks"#

If we were working with letters that are all unique, say with the word SPINE, we'd be picking 3 letters at a time from 5 letters in total, giving:

#P_(5,3)=(5!)/(2!)=120/2=60# "words"

But we have SPINS - and so the second S is a duplicate.

To deal with this, we can break down the calculations into different situations. One is where we draw up to 1 S and the other is where we draw both.

Up to 1 S

This gives a population of 4 letters being drawn 3 at a time:

#P_(4,3)=(4!)/(1!)=24/1=24# "words"

Both S's

We can put the letter that isn't an S into spots 1, 2, or 3, giving 3 choices. There are 3 letters that aren't S's. And so we have:

#3xx3=9# "words"

Total

#24+9=33# "words"