# To which substance is dilute sulfuric acid added to prepare lead(II) sulfate?

May 1, 2017

#### Answer:

Any soluble lead(II) salt.........

#### Explanation:

So $\text{solution A}$ is the obvious choice.

And we could write the reaction as....................:

$P b {\left(N {O}_{3}\right)}_{2} \left(a q\right) + {H}_{2} S {O}_{4} \left(a q\right) \rightarrow P b S {O}_{4} \left(s\right) \downarrow + 2 H N {O}_{3} \left(a q\right)$

This is a very poor multiple choice question (most multiple choice questions are!), because I am willing to bet that sulfuric acid added to lead carbonate would decompose the carbonate, bring the salt briefly up into solution, and then the insoluble lead sulfate would precipitate:

$P b C {O}_{3} \left(s\right) + {H}_{2} S {O}_{4} \left(a q\right) \rightarrow P b S {O}_{4} \left(s\right) \downarrow + C {O}_{2} \left(g\right) \uparrow + {H}_{2} O \left(l\right)$

The oxide is possibly too insoluble. I might do this reaction tomorrow to see if I am right.