Transmittance of a solution? Question #3# only

1 Answer
Apr 25, 2017

Answer:

a) #A = 0.118#
b) #a = 0.98 " L " mol^(-1) cm^(-1)#
c) #c = 7.9 *10^(-6)M#

Explanation:

3.a) Use the formula:
#A = 2 - log_10(%T)#
Note: A is the absorbance and %T is the percent of transmittance.
#A = 2 - log_10(76.2)#
#A = 0.118045029#

#A = 0.118#

b) Use the formula:
#A = abc#
Note: A is absorbance, a is molar absorptivity, b is path length, and c is concentration.

#0.118 = a * 1.5cm * 0.0802M#

#a = 0.981255434 " L " mol^(-1) cm^(-1)#

#a = 0.98 " L " mol^(-1) cm^(-1)#

c) #c = A/(ab)#

#c = 0.118/((10000 L/(mol*cm))(1.5 cm))#

#c = 0.00000787 M#

#c = 7.9 *10^(-6)M#