Trapezoid RSTV had median UK. If VT= $4x-6$ and UK = $3x+2$ and RS = $x+12$ , find $x$ ?

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Answer 1 · 2016-01-03T05:16:43

$x=2$

The median of any trapezoid is equal to the average of the bases.

The average of the bases can also be written as the sum of the bases over two.

Thus, since the bases are $VT$ and $RS$ , and the median $UK$ ,

$(VT+RS)/2=UK$

Substitute in the lengths.

$((4x-6)+(x+12))/2=3x+2$

Multiply both sides by $2$ .

$4x-6+x+12=6x+4$

Simplify.

$5x+6=6x+4$

$x=2$

We can check by plugging in $2$ .

$VT=2$
$UK=8$
$RS=14$

$8$ indeed is the average of $2$ and $14$ , so $x=2$ .

Trapezoid RSTV had median UK. If VT= 4x-64x-6 and UK = 3x+23x+2 and RS = x+12x+12, find xx?