Question

Trent told his friends it would take him 90 minutes to mow the lawn. It only took him 75 minutes. What is his percent error?

Answer 1

His percent error is `16.bar6%`

Explanation:

Trent estimated his time to be `90m`

Actual time was `75m`

Error was `90m-75m=15m`

Fractional error was then `(15cancelm)/(90cancelm)`

So `%` error is `cancel15/(cancel(90)6)xx100=100/6%=16.bar6%`