Triangle A has an area of #12 # and two sides of lengths #7 # and #7 #. Triangle B is similar to triangle A and has a side with a length of #19 #. What are the maximum and minimum possible areas of triangle B?

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Answer 1 · 2017-12-21T13:01:03

Area of triangle B = 88.4082

Since triangle A is isosceles, triangle B will also be isosceles.

Sides of Triangles B & A are in the ratio of 19 : 7

Areas will be in the ratio of #19^2 : 7^2 = 361 : 49#

#:. Area of triangle B = (12 * 361) / 49 = 88.4082#