Triangle A has an area of 18  and two sides of lengths 8  and 8 . Triangle B is similar to triangle A and has a side of length 8 . What are the maximum and minimum possible areas of triangle B?

Dec 21, 2017

Area of triangle B = 18 as the two triangles are congruent.

Explanation:

$\Delta s A \mathmr{and} B$ are similar.

Since triangle A is isosceles, triangle B will also be isosceles.

Also sides of triangles A & B are equal (both are 8 in length), both the triangles are identical.

Hence area of triangle A = Area of triangle B = 18