Triangle A has sides of lengths #32 #, #36 #, and #24 #. Triangle B is similar to triangle A and has a side of length #8 #. What are the possible lengths of the other two sides of triangle B?

1 Answer
Feb 15, 2016

The other two sides of B are
#color(white)("XXX"){9,6}#
or
#color(white)("XXX"){7 1/9, 5 1/3}#
or
#color(white)("XXX"){12,10 2/3}#

Explanation:

Denote the given side of B as #B_1=8#
and
the sides of A as #A_1, A_2, A_3# such that #A_1# corresponds to #B_1#

Given: #{A_1,A_2,A_3}={32,36,24}#

Case 1 : #A_1=32#
#color(white)("XXX")#The ratio of #A_1:B_1 = 32:8=4:1#
#color(white)("XXX")#All corresponding sides must be in this ratio
#color(white)("XXX")rarr B_x=A_x/4#
#color(white)("XXX")#So the other two sides of B must have lengths
#color(white)("XXX")36/4=9 and 24/4=6#

Case 1 : #A_1=36#
#color(white)("XXX")#The ratio of #A_1:B_1 = 36:8=4.5:1#
#color(white)("XXX")#All corresponding sides must be in this ratio
#color(white)("XXX")rarr B_x=A_x/4.5#
#color(white)("XXX")#So the other two sides of B must have lengths
#color(white)("XXX")32/4.5=7 1/9 and 24/4.5=5 1/3#

Case 1 : #A_1=24#
#color(white)("XXX")#The ratio of #A_1:B_1 = 24:8=3#
#color(white)("XXX")#All corresponding sides must be in this ratio
#color(white)("XXX")rarr B_x=A_x/3#
#color(white)("XXX")#So the other two sides of B must have lengths
#color(white)("XXX")36/3=12 and 32/3=10 2/3#