Two bodies of masses #m_1 and m_2# are connected by a light string which passes over a frictionless massless pulley. If the pulley is moving upward with uniform acceleration #g/2#, what is the tension in the string?

1 Answer
Dec 1, 2017

# T = m(g+a) = m (g + g/2) = 3/2 mg#

Explanation:

Consider the net force acting an the hanging mass,
#vec F_{"net"} = vec T + mvec g = T - mg;#

Newton's Second Law: #\qquad vec F_{"net"} = mveca; \qquad T -mg = ma; #
# T = m(g+a) = m (g + g/2) = 3/2 mg#