Two bodies of masses $m_{1} and m_{2}$ $m_1 and m_2$ are connected by a light string which passes over a frictionless massless pulley. If the pulley is moving upward with uniform acceleration $\frac{g}{2}$ $g/2$ , what is the tension in the string?

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Answer 1 · 2017-12-01T06:04:10

$T = m (g + a) = m (g + \frac{g}{2}) = \frac{3}{2} m g$ $T = m(g+a) = m (g + g/2) = 3/2 mg$

Consider the net force acting an the hanging mass,
${\to F}_{net} = \to T + m \to g = T - m g;$ $vec F_{"net"} = vec T + mvec g = T - mg;$

Newton's Second Law: $\qquad vec F_{"net"} = mveca; \qquad T -mg = ma;$
$T = m(g+a) = m (g + g/2) = 3/2 mg$

Two bodies of masses m_1 and m_2m1andm2m_1 and m_2 are connected by a light string which passes over a frictionless massless pulley. If the pulley is moving upward with uniform acceleration g/2g2g/2, what is the tension in the string?