Two charges of # -1 C # and # 5 C # are at points # (1,0,3 ) # and # ( -3, 5,-81 )#, respectively. Assuming that both coordinates are in meters, what is the force between the two points?

1 Answer
Jan 5, 2018

Answer:

The force is #=-6.3*10^6N#

Explanation:

The force between #2# charges #q_1# and #q_2# is

#F=k(q_1*q_2)/r^2#

Where #r# is the distance between the charges.

And the constant #k=9*10^9Nm^2C^-2#

The charge #q_1=-1C#

The charge #q_2=5C#

The distance is

#r=sqrt((-3-1)^2+(5-0)^2+(-81-3)^2)=sqrt(16+25+7056)#

#=sqrt(7097)#

Therefore,

The force is #=9*10^9*((-1)*(5))/(7097)=-0.0063*10^9=-6.310^6N#

The negative sign indicates that the force is attractive