Two charges of -1 C −1C and 5 C 5C are at points (1,0,3 ) (1,0,3) and ( -3, 5,-81 )(−3,5,−81), respectively. Assuming that both coordinates are in meters, what is the force between the two points?

1 Answer
Narad T.
Jan 5, 2018

The force is =-6.3*10^6N=−6.3⋅106N

Explanation:

The force between 22 charges q_1q1 and q_2q2 is

F=k(q_1*q_2)/r^2F=kq1⋅q2r2

Where rr is the distance between the charges.

And the constant k=9*10^9Nm^2C^-2k=9⋅109Nm2C−2

The charge q_1=-1Cq1=−1C

The charge q_2=5Cq2=5C

The distance is

r=sqrt((-3-1)^2+(5-0)^2+(-81-3)^2)=sqrt(16+25+7056)r=√(−3−1)2+(5−0)2+(−81−3)2=√16+25+7056

=sqrt(7097)=√7097

Therefore,

The force is =9*10^9*((-1)*(5))/(7097)=-0.0063*10^9=-6.310^6N=9⋅109⋅(−1)⋅(5)7097=−0.0063⋅109=−6.3106N

The negative sign indicates that the force is attractive

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