Question

Two charges of `1 C` and `-8 C` are at points `(6,-4,2)` and `( 4,-3,7)`, respectively. Assuming that both coordinates are in meters, what is the force between the two points?

Answer 1

-`2.4*(10^9)` N

Explanation:

Distance between the two charges is `√{(6-4)^2+(-4-(-3))^2+(2-7)^2}`meters or √30 meters
Hence,force acting in between them =F= `(1/(4pie0))((Q1Q2)/(r^2))` putting the values we get,F=-`2.4*(10^9)`N