# Two charges of  1 C  and  -8 C  are at points  (6,-4,2)  and  ( 4,-3,7), respectively. Assuming that both coordinates are in meters, what is the force between the two points?

-$2.4 \cdot \left({10}^{9}\right)$ N
Distance between the two charges is √{(6-4)^2+(-4-(-3))^2+(2-7)^2} meters or √30 meters
Hence,force acting in between them =F= $\left(\frac{1}{4 \pi e 0}\right) \left(\frac{Q 1 Q 2}{{r}^{2}}\right)$ putting the values we get,F=-$2.4 \cdot \left({10}^{9}\right)$N