Two charges of # -2 C # and # 4 C # are at points # (4, -2, -1) # and # ( -1 , 3, -8 )#, respectively. Assuming that both coordinates are in meters, what is the force between the two points?

1 Answer

Answer:

#F=726,464,646.5" ""Newtons"#

Explanation:

Compute the distance #r# between the two charges

Let #P_2(x_2, y_2, z_2)=(4, -2, -1)#
Let #P_1(x_1, y_1, z_1)=(-1, 3, -8)#

#r=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#

#r=sqrt((4--1)^2+(-2-3)^2+(-1--8)^2)#

#r=sqrt(25+25+49)#

#r=sqrt(99)" "#meters

#F=(k_e*abs(q_1*q_2))/r^2#

#F=((8.99 x 10^9)*abs(-2*4))/(sqrt(99))^2#

#F=726,464,646.5" ""Newtons"#

God bless....I hope the explanation is useful.