Two charges of # -2 C # and # -7 C# are positioned on a line at points # 3 # and # 4 #, respectively. What is the net force on a charge of # -5 C# at # 0 #?

1 Answer
Oct 18, 2016

Answer:

#"Net force on charge of -5C is "2.969" "N#

Explanation:

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#vec F_1:"Force between "q_A" and "q_C#

#vec F_2:"Force between "q_B" and "q_C#

#vec F_C:" vectorial sum of "F_1" and "F_2" (net force on charge of -5C)"#

#vec F_1=cancel(9).10^9(q_A*q_C)/cancel(3)^2=10^9*q_A*q_C=(-2)*(-5)*10^9#

#vec F_1=10*10^9 " "N#

#vec F_2=9*10^9(q_B*q_C)/4^2=9*10^9((-7)*(-5))/16#

#vec F_2=(35*9*10^9)/16=19.69*10^9" "N#

#vec F_C=vec F_1+vec F_2#

#vec F_C=10*10^9+19.69*10^9#

#vec F_C=29.69*10^9#

#vec F_C=2.969*10^10 " "N#