Question

Two charges of `-3 C` and `2 C` are at points `(-9,3,8)` and `( 3,-6,7)`, respectively. Assuming that both coordinates are in meters, what is the force between the two points?

Answer 1

`F~=-0,239*10^9 N " Force is attractive"`

Explanation:

`"distance between(-9,3,8) and (3,-6,7):"`
`r^2=(3-(-9))^2+(-6-3)^2+(7-8)^2`
`r^2=144+81+1`
`r^2=226`
`"force between two charges is given by Coulomb's law:"`
`F=(k*q_1*q_2)/(r^2)`
`F=(9*10^9*(-3)*2)/(226)`
`F=(-54*10^9)/226`
`F~=-0,239*10^9 N " Force is attractive"`