Question

Two charges of `-3 C` and `2 C` are positioned on a line at points `6` and `4`, respectively. What is the net force on a charge of `3 C` at `2`?

Answer 1

`F_N~=8,44*10^9N`

Explanation:

`"distance between 2C and 3C is :"4-2=2`
`"distance between -3C and 3C is :"6-2=4`
`"Force between two charges is given by :"F=(k*q_1*q_2)/d^2`
`"Force between 2C and 3C :" F_(2C larr 3C)=(k*2*3)/2^2=(3*k)/2`
`"Force between -3C and 3C :" F_(-3C rarr 3C)=(k*3*(-3))/4^2`
`F_(-3C rarr 3C)=(-9*k)/16`
`"Net Force on the charge of 3C :"F_(2C larr 3C)+F_(-3C rarr 3C )`
`F_N=(3*k)/2-(9*k)/16`
`F_N=(24*k-9*k)/16`
`F_N=(15*k)/16`
`F_N=(15*9*10^9)/16`
`F_N~=8,44*10^9N`