Two charges of # 3 C # and # -3 C# are positioned on a line at points # 6 # and # 2 #, respectively. What is the net force on a charge of # 4 C# at # 1 #?

1 Answer
Jan 1, 2018

Answer:

The net force is #=-103.7*10^9N#

Explanation:

The net force between the charges is

#F=k(Q_1Q_3)/r_1^2+k(Q_2Q_3)/r_2^2#

Where #r# is the distance between the charges

The constant #k=9*10^9Nm^2/C^2#

The charge #Q_1=3C# at #(6,0)#

The charge #Q_2=-3C# at #(2,0)#

The charge #Q_3=4C# at #(1,0)#

The net force is

#F=910^9*(3*4)/(5)^2+910^9(-3*4)/(1)^2=-103.7*10^9N#

The negative sign indicates that the force is attractive